A parallel plate capacitor with air as medium between the plates has a capacitance of $10 \mu \mathrm{F}$ . The area of capacitor is divided into two equal halves and filled with two media as shown in the figure having dielectric constant $k_{1} = 2$ and $k_2 = 4$ . The capacitance of the system will now be
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$C_{R} = C_{1} + C_{2} = \frac{k_{1} \varepsilon_{0} A_{1}}{d} + \frac{k_{2} \varepsilon_{0} A_{2}}{d}$
$= \frac{2 \times \varepsilon_0 \frac{A}{2}}{d} + \frac{4 \times \varepsilon_0 \frac{A}{2}}{d}$ $= 2 \times \frac{10}{2} + 4 \times \frac{10}{2} = 30 \mu F$
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